5t^2-19t+25=0

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Solution for 5t^2-19t+25=0 equation:


Simplifying
5t2 + -19t + 25 = 0

Reorder the terms:
25 + -19t + 5t2 = 0

Solving
25 + -19t + 5t2 = 0

Solving for variable 't'.

Begin completing the square.  Divide all terms by
5 the coefficient of the squared term: 

Divide each side by '5'.
5 + -3.8t + t2 = 0

Move the constant term to the right:

Add '-5' to each side of the equation.
5 + -3.8t + -5 + t2 = 0 + -5

Reorder the terms:
5 + -5 + -3.8t + t2 = 0 + -5

Combine like terms: 5 + -5 = 0
0 + -3.8t + t2 = 0 + -5
-3.8t + t2 = 0 + -5

Combine like terms: 0 + -5 = -5
-3.8t + t2 = -5

The t term is -3.8t.  Take half its coefficient (-1.9).
Square it (3.61) and add it to both sides.

Add '3.61' to each side of the equation.
-3.8t + 3.61 + t2 = -5 + 3.61

Reorder the terms:
3.61 + -3.8t + t2 = -5 + 3.61

Combine like terms: -5 + 3.61 = -1.39
3.61 + -3.8t + t2 = -1.39

Factor a perfect square on the left side:
(t + -1.9)(t + -1.9) = -1.39

Can't calculate square root of the right side.

The solution to this equation could not be determined.

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